Question

Bài 1: Tính 

1) \(\frac{2}{5}\) . \(\frac{1}{2}\)+ \(\frac{1}{3}\)

2) ( \(\frac{5}{7}\) - \(\frac{2}{5}\) ) : \(\frac{11}{7}\)

3) A = \(1-\frac{2}{3}+\frac{1}{4}\)
            ________
           \(2-\frac{1}{3}\) + \(\frac{1}{6}\)
Các bạn giải cụ thể ra giúp mk nhé, mk cảm ơn

Answer 1

1) \(\frac{2}{5}\cdot\frac{1}{2}+\frac{1}{3}=\frac{1}{5}+\frac{1}{3}=\frac{8}{15}\)

2)\(\left(\frac{5}{7}-\frac{2}{5}\right):\frac{11}{7}=\frac{5}{7}:\frac{11}{7}-\frac{2}{5}:\frac{11}{7}=\frac{5}{7}\cdot\frac{7}{11}-\frac{2}{5}\cdot\frac{7}{11}=\frac{5}{11}-\frac{14}{55}=\frac{1}{5}\)

3)\(\frac{1-\frac{2}{3}+\frac{1}{4}}{2-\frac{1}{3}+\frac{1}{6}}=\frac{12-8+3}{12}:\frac{12-2+1}{6}=\frac{7}{12}\cdot\frac{\frac{6}{11}7}{22}\)