\(2xy+x=5y\)
\(\Rightarrow2\left(2xy+x\right)=2.5y\)
\(\Rightarrow4xy+2x=10y\)
\(\Rightarrow2x\left(2y+1\right)-10y-5=-5\)
\(\Rightarrow2x\left(2y+1\right)-5\left(2y+1\right)=-5\)
\(\Rightarrow\left(2x-5\right)\left(2y+1\right)=-5\)
Ta có bảng sau:
| 2x - 5 | 1 | -1 | 5 | -5 |
| 2y + 1 | -5 | 5 | -1 | 1 |
| x | 3 | 2 | 5 | 0 |
| y | -3 | 2 | -1 | 0 |
Vậy cặp số \(\left(x;y\right)\) là \(\left(3;-3\right);\left(2;2\right);\left(5;-1\right);\left(0;0\right)\)
\(2xy+x=5y\)
\(=>2\left(2xy+x\right)=2.5y\)
=> \(4xy+2x=10y\)
=> \(2x\left(2y+1\right)-10y-5=-5\)
=> \(2x+\left(2y+1\right)-5\left(2y+1\right)=-5\)
=> \(\left(2x-5\right)\left(2y+1\right)=-5\)
Ta có :
|
2x - 5 |
1 |
-1 |
5 |
5 |
|
2y + 1 |
-5 |
5 |
-1 |
-1 |
|
x |
3 |
2 |
5 |
0 |
|
y |
-3 |
2 |
-1 |
0 |
=> Các cặp số x,y là {3;-3};{2;2};{5,-1};{0,0}
