Question

Bài 1: Phân tích đa thức thành nhân tử:

a) x² -2x -y² +2y

b) 2x +2y -x² -xy

 

 

Answer 1

a) \(x^2-2x-y^2+2y\)

\(=\left(x^2-y^2\right)-\left(2x-2y\right)\)

\(=\left(x-y\right)\left(x+y\right)-2\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y-2\right)\)

b) \(2x+2y-x^2-xy\)

\(=2\left(x+y\right)-x\left(x+y\right)=\left(x+y\right)\left(2-x\right)\)

Answer 2

x²-y² -2x+2y=(x+y)(x-y)-2(x-y)=(x-y)(x-y-2)

2(x+y)-x(x+y)=(x+y)(2-x)

Answer 3

a) x^2-2x-y^2+2y

=x(x-2)-y(y-2)

=(x-y)(x-2)

b) 2x + 2y - x^2 -xy

= 2(x+y) - x(x+y)

= (2 - x)(x+y)