a, Diện tích mặt đáy:
\(S=\dfrac{V}{h}=\dfrac{2x^3+6x^2-8x}{2x}=\left(2x^3:2x\right)+\left(6x^2:2x\right)-\left(8x:2x\right)=x^2+3x-4\)
b, \(h=10\left(dm\right)\\ \Leftrightarrow 2x=10\left(dm\right)\\ \Leftrightarrow x=5\left(dm\right)\\ \Rightarrow S=x^2+3x-4\left(dm^2\right)=5^2+3.5-4=36\left(dm^2\right)\\ V=2x^3+6x^2-8x\left(dm^3\right)=2.5^3+6.5^2-8.5=360\left(dm^3\right)\)