Question

Bài 1. Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:

1a) 1,2 – (x – 0,8) = –2(0,9 + x) b) 3,6 – 0,5(2x + 1) = x – 0,25(2 – 4x)

c) 2,3x – 2(0,7 + 2x) = 3,6 – 1,7x d) 0,1 – 2(0,5t – 0,1) = 2(t – 2,5) – 0,7

e) 3 + 2,25x +2,6 = 2x + 5 + 0,4x f) 5x + 3,48 – 2,35x = 5,38 – 2,9x + 10,42

2

a) 5 – (x – 6) = 4(3 – 2x) b) 2x(x + 2)² – 8x² = 2(x – 2)(x² + 2x + 4)

c) 7 – (2x + 4) = – (x + 4) d) (x – 2)³ + (3x – 1)(3x + 1) = (x + 1)³

e) (x + 1)(2x – 3) = (2x – 1)(x + 5) f) (x – 1)³ – x(x + 1)² = 5x(2 – x) – 11(x + 2)

g) (x – 1) – (2x – 1) = 9 – x h) (x – 3)(x + 4) – 2(3x – 2) = (x – 4)²

i) x(x + 3)² – 3x = (x + 2)³ + 1 j) (x + 1)(x² – x + 1) – 2x = x(x + 1)(x – 1)

Answer 1