Question

Bài 1 :

a) (-2)^5 : (-2)^3

b)( -y ) ^7 : (-y )^3

c) x^12 : (-x^10)

d) (2x^6):(2x)^3

e) (-3x)^5 : (-3x)^2

f) (xy^2 )^4 : (xy^2)^2

Answer 1

a)\(^{ }\left(-2\right)^5:\left(-2\right)^3=\left(-2\right)^{5-3}=\left(-2\right)^2=4\)

b)\(\left(-y\right)^7:\left(-y\right)^3=\left(-y\right)^{7-3}=\left(-y\right)^4\)

c)\(x^{12}:\left(-x^{10}\right)=-\left(x^{12}\right):\left(x^{10}\right)=-\left(x^{12-10}\right)=-\left(x^2\right)\)

d)\(\left(2x^6\right):\left(2x\right)^3=2\left(x^6\right):8\left(x^3\right)=\frac{2}{8}x^{6-3}=\frac{1}{4}x^3\)

e)\(\left(-3x\right)^5;\left(-3x\right)^3=\left(-3x\right)^{5-3}=\left(-3x\right)^2\)

f)\(\left(xy^2\right)^4:\left(xy^2\right)^2=\left(xy^2\right)^{4-2}=\left(xy^2\right)^2\)

Answer 2

các cậu làm ra vở rồi chup thì càng tốt ạ ( làm theo kiểu kẻ cột ý á , kiểu đặt phép tính ý )