b) \(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)
\(\left(x+\frac{1}{2}\right)^2=\left(\frac{1}{4}\right)^2\)
\(\Rightarrow x+\frac{1}{2}=\frac{1}{4}\)
\(x=\frac{1}{4}-\frac{1}{2}\)
\(x=\frac{1}{4}-\frac{1}{4}\)
x= 0
Vậy x = 0
a) \(x:\left(\frac{1}{3}\right)^3=\frac{1}{3}\)
\(x:\frac{1}{27}=\frac{1}{3}\)
\(x=\frac{1}{3}.\frac{1}{27}\)
\(x=\frac{1}{81}\)
Vậy x =\(\frac{1}{3}\)
b) \(\left(x:\frac{1}{2}\right)^2=\frac{1}{16}\)
\(\left(x:\frac{1}{2}\right)^2=\left(\frac{1}{4}\right)^2\)
\(\Rightarrow x:\frac{1}{2}=\frac{1}{4}\)
\(x=\frac{1}{4}.\frac{1}{2}\)
\(x=\frac{1}{8}\)
Vậy x=\(\frac{1}{8}\)
Chúc bn học tốt!
câu a chỗ vậy mik viết nhầm
phải là \(\frac{1}{81}\)
a) \(x:\left(\frac{1}{3}\right)^3=\frac{1}{3}\)
\(\Rightarrow x=\left(\frac{1}{3}\right).\left(\frac{1}{3}\right)^3\)
\(\Rightarrow x=\left(\frac{1}{3}\right)^4\)
\(\Rightarrow x=\frac{1}{81}\)
Vậy \(x=\frac{1}{81}.\)
b) \(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)
\(\Rightarrow\left(x+\frac{1}{2}\right)^2=\left(\pm\frac{1}{4}\right)^2\)
\(\Rightarrow x+\frac{1}{2}=\pm\frac{1}{4}.\)
\(\Rightarrow\left[{}\begin{matrix}x+\frac{1}{2}=\frac{1}{4}\\x+\frac{1}{2}=-\frac{1}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{1}{4}-\frac{1}{2}\\x=\left(-\frac{1}{4}\right)-\frac{1}{2}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\frac{1}{4}\\x=-\frac{3}{4}\end{matrix}\right.\)
Vậy \(x\in\left\{-\frac{1}{4};-\frac{3}{4}\right\}.\)
Chúc bạn học tốt!
