Question

A={x thuộc Z/-6<x<3}

 tính tổng các phần tử 

Answer 1

\(A=\left\{-5;-4;-3;-2;-1;0;1;2\right\}\)
Tổng các phần tử:
\(-5+-4+-3+-2+-1+0+1+2=-5+-4+-3+\left(-1+1\right)+\left(-2+2\right)\)
\(=-12+0+0=-12\)

Answer 2

A={-5;-4;-3;-2;-1;0;1;2}

Tổng A=-5+(-4)+(-3)=-12

Answer 3

\(A=\left\{x\in Z\left|\right|-6< x< 3\right\}\)

\(A=\left\{-5;-4;-3;...;1;2\right\}.\)

\(A=\left\{-5+-4+-3+...+1+2\right\}\)

\(A=-12.\)

Answer 4

\(=>x\in\left\{-5;-4;-3;-2;-1;0;1;2\right\}\)

\(-5+\left(-4\right)+\left(-3\right)+\left(-2\right)+\left(-1\right)+0+1+2\\ =-5-4-3-2+2-1+1\\ =-12\)