Question

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1) (x + 1) . (y + 2) = -6

2) (x - 1) . (2y - 3) = -12

3) (2x - 1) . (2y + 1) = 15

4) (x + 2) . (xy - 1) = 7

5) xy - 2x + y = 0

6) 2x - xy - 3y = 0

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Answer 1

1) \(\left(x+1\right)\left(y+2\right)=-6\)

TH1 : \(\left[{}\begin{matrix}x+1=6\\y+2=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\y=-3\end{matrix}\right.\)

TH2 : \(\left[{}\begin{matrix}x+1=-6\\y+2=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-7\\y=-1\end{matrix}\right.\)

TH3 : \(\left[{}\begin{matrix}x+1=1\\y+2=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\y=-8\end{matrix}\right.\)

TH4 : \(\left[{}\begin{matrix}x+1=-1\\y+2=6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-2\\y=4\end{matrix}\right.\)

TH5 : \(\left[{}\begin{matrix}x+1=2\\y+2=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\y=-5\end{matrix}\right.\)

TH6 : \(\left[{}\begin{matrix}x+1=-2\\y+2=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\\y=1\end{matrix}\right.\)

TH7 : \(\left[{}\begin{matrix}x+1=3\\y+2=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\y=-4\end{matrix}\right.\)

TH8 : \(\left[{}\begin{matrix}x+1=-3\\y+2=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\y=0\end{matrix}\right.\)

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