Question

ai đó giúp mình trả lời câu hỏi này với

a)(1+\(\frac{3}{7}\)).x=1-1\(\frac{1}{7}\)

b)(4\(\frac{46}{65}+x\)).1\(\frac{1}{12}\)=5,75

Answer 1

a) Ta có: \(\left(1+\frac{3}{7}\right)\cdot x=1-1\frac{1}{7}\)

\(\Leftrightarrow\frac{10}{7}\cdot x=1-\frac{8}{7}\)

\(\Leftrightarrow\frac{10}{7}\cdot x=\frac{-1}{7}\)

hay \(x=-\frac{1}{10}\)

Vậy: \(x=-\frac{1}{10}\)

b) Ta có: \(\left(4\frac{46}{65}+x\right)\cdot1\frac{1}{12}=5,75\)

\(\Leftrightarrow\left(\frac{306}{65}+x\right)\cdot\frac{13}{12}=\frac{23}{4}\)

\(\Leftrightarrow x+\frac{306}{65}=\frac{23}{4}:\frac{13}{12}=\frac{23}{4}\cdot\frac{12}{13}=\frac{69}{13}\)

hay \(x=\frac{69}{13}-\frac{306}{65}=\frac{345}{65}-\frac{306}{65}\)

\(\Leftrightarrow\)\(x=\frac{3}{5}\)

Vậy: \(x=\frac{3}{5}\)