Question

a)\(\frac{-7}{12}+\left(\frac{1}{4}+\frac{2}{3}\right)\)

b)0,5 . \(\sqrt{100}\)-\(\sqrt{\frac{1}{4}}\)

c)(-3)\(^2\) . \(\left(\frac{3}{4}-0,25\right)\)-\(\left|3\frac{1}{2}-1\frac{1}{2}\right|\)

Answer 1

b, 0,5 .\(\sqrt{100}\)-\(\sqrt{\frac{1}{4}}\)

=\(\frac{1}{2}\).10-\(\frac{1}{2}\)

=\(\frac{1}{2}\).(10-1)

=\(\frac{1}{2}\).9

=\(\frac{9}{2}\)

Answer 2

???

Answer 3

a) \(\frac{-7}{12}+\left(\frac{1}{4}+\frac{2}{3}\right)\)

\(=\frac{-7}{12}+\left(\frac{3}{12}+\frac{8}{12}\right)\)

\(=\frac{-7}{12}+\frac{11}{12}\)

\(=\frac{5}{12}\)

Answer 4

b) \(0,5.\sqrt{100}-\sqrt{\frac{1}{4}}\)

\(=\frac{1}{2}.10-\frac{1}{2}\)

\(=\frac{5}{1}-\frac{1}{2}\)

\(=\frac{10}{2}-\frac{1}{2}\)

\(=\frac{9}{2}\)

Answer 5

c,\(\left(-3\right)^2\).(\(\frac{3}{4}\)-0,25)-|\(3\frac{1}{2}\)-\(1\frac{1}{2}\)|

=9.(\(\frac{3}{4}\)-\(\frac{1}{4}\))-|\(\frac{7}{2}\)-\(\frac{3}{2}\)|

=9.\(\frac{2}{4}\)-\(\frac{4}{2}\)

=9.\(\frac{1}{2}\)-2

=\(\frac{9}{2}\)-2

=\(\frac{9}{2}\)-\(\frac{4}{2}\)

=\(\frac{5}{2}\)