\(A=\dfrac{5}{4}.\left(5-\dfrac{4}{3}\right).\left(\dfrac{-1}{11}\right)\)
\(A=\dfrac{5}{4}.\dfrac{11}{3}.\dfrac{-1}{11}=\dfrac{5}{4}.\dfrac{-1}{3}=-\dfrac{5}{12}\)
A= \(\dfrac{5}{4}\).(5-\(\dfrac{4}{3}\)).(-\(\dfrac{1}{11}\))
A=\(\dfrac{5}{4}\).(\(\dfrac{15}{3}\)- \(\dfrac{4}{3}\)).(-\(\dfrac{1}{11}\))
A=\(\dfrac{5}{4}\). \(\dfrac{11}{3}\).\(\dfrac{-1}{11}\)
A=\(\dfrac{5.11.\left(-1\right)}{4.3.11}\)
A=\(\dfrac{5.1.\left(-1\right)}{4.3.1}\)
A=\(\dfrac{-5}{12}\)
Vậy A=\(\dfrac{-5}{12}\)