a)Ta có: \(VT=7^6+7^5-7^4\)
\(=7^4\left(7^2+7-1\right)=7^4\cdot55⋮55\)
Vậy \(7^6+7^5-7^4⋮55\)
b)\(A=1+5+...+5^{100}\)
\(5A=5\left(1+5+...+5^{100}\right)\)
\(5A=5+5^2+...+5^{101}\)
\(5A-A=\left(5+5^2+...+5^{101}\right)-\left(1+5+...+5^{100}\right)\)
\(4A=5^{101}-1\Rightarrow A=\frac{5^{101}-1}{4}\)