Question

A1=150 nu

G1=300 nu

A=?

T=?

lADN=?

A2=300 nu

G2=600 nu 

G=?

X=?

Chu kì xoắn C=?

 

Answer 1

- Đề kiểu gì thế ?

\(A=T=A_1+A_2=150+300=450\left(nu\right)\)

\(G=X=G_1+G_2=300+600=900\left(nu\right)\)

\(\Rightarrow N=2A+2G=2900\left(nu\right)\)

\(\Rightarrow L=3,4.\dfrac{N}{2}=4930\left(\overset{o}{A}\right)\)

\(\Rightarrow C=\dfrac{L}{34}=145\)

Answer 2

A = T = A1 + A2 = 150 + 300 = 450 (nu)

G = X = G1 + G2 = 300 + 600 = 900 (nu)

-> \(L_{ADN}=\dfrac{N}{2}.3,4=\left(A+G\right).3,4=4590\left(A^o\right)\)

Chu kì xoắn : \(C=\dfrac{N}{20}=\dfrac{2A+2G}{20}=135\left(ckì\right)\)