Question

A) x : \(\left(-\frac{1}{3^{^{ }}}\right)^{3^{ }}\) = \(\frac{-1}{3}\)

b) \(\frac{3}{4}\) : \(\frac{41}{99}\) = x : \(\frac{75}{90}\)

c) x + \(\left|-\frac{1}{2}\right|\) = \(3\frac{1}{3}\) - \(4\frac{1}{2}\)

GIÚP MIH NHA, MIH CẢM ƠN

Answer 1

a) \(x:\left(-\frac{1}{3}\right)^3=-\frac{1}{3}\)

\(\Rightarrow x=\left(-\frac{1}{3}\right).\left(-\frac{1}{3}\right)^3\)

\(\Rightarrow x=\left(-\frac{1}{3}\right)^4\)

\(\Rightarrow x=\frac{1}{81}\)

Vậy \(x=\frac{1}{81}.\)

b) \(\frac{3}{4}:\frac{41}{99}=x:\frac{75}{90}\)

\(\Rightarrow\frac{297}{164}=x:\frac{75}{90}\)

\(\Rightarrow x=\frac{297}{164}.\frac{75}{90}\)

\(\Rightarrow x=\frac{495}{328}\)

Vậy \(x=\frac{495}{328}.\)

c) \(x+\left|-\frac{1}{2}\right|=3\frac{1}{3}-4\frac{1}{2}\)

\(\Rightarrow x+\frac{1}{2}=\frac{10}{3}-\frac{9}{2}\)

\(\Rightarrow x+\frac{1}{2}=-\frac{7}{6}\)

\(\Rightarrow x=\left(-\frac{7}{6}\right)-\frac{1}{2}\)

\(\Rightarrow x=-\frac{5}{3}\)

Vậy \(x=-\frac{5}{3}.\)

Chúc bạn học tốt!