a) -(x-3)= -(2-5)
=> x-3 = 2-5
=> x = 2-5+3
=> x = 0
Vậy x=0
b) -(3x-4)=-(2x+1)
=> 3x-4 = 2x+1
=> 3x-2x = 4+1
=> x = 5
Vậy x=5
a) \(-\left(x-3\right)=-\left(2-5\right)\)
\(-x+3=-2+5\)
\(-x=-2+5-3\)
\(-x=0\)
\(x=0\)
\(-\left(3x-4\right)=-\left(2x+1\right)\)
\(-3x+4=-2x-1\)
\(-3x+2x=-1-4\)
\(-x=-5\)
\(x=5\)