Question

a) \(\frac{21}{47}\) + \(\frac{9}{45}\) + \(\frac{26}{47}\) + \(\frac{4}{5}\)

b) 12 x \(\left(-\frac{2}{3}\right)\)² +\(\frac{4}{3}\)

c) 12,5 x \(\left(-\frac{5}{7}\right)\) + 1,5 x \(\left(-\frac{5}{7}\right)\)

d) \(\frac{4}{5}\) x \(\left(\frac{7}{2}+\frac{1}{4}\right)\)²

Answer 1

a) \(\frac{21}{47}+\frac{9}{45}+\frac{26}{47}+\frac{4}{5}\)

\(=\left(\frac{21}{47}+\frac{26}{47}\right)+\left(\frac{9}{45}+\frac{4}{5}\right)\)

\(=\frac{47}{47}+\left(\frac{1}{5}+\frac{4}{5}\right)\)

\(=1+1=2\)

b) \(12.\left(-\frac{2}{3}\right)^2+\frac{4}{3}\)

\(=12.\frac{4}{9}+\frac{4}{3}\)

\(=\frac{16}{3}+\frac{4}{3}\)

\(=\frac{20}{3}\)

c) \(12,5.\left(-\frac{5}{7}\right)+15.\left(-\frac{5}{7}\right)\)

\(=\left(-\frac{5}{7}\right).\left(12,5+15\right)\)

\(=\left(-\frac{5}{7}\right).27,5\)

\(=\left(-\frac{5}{7}\right).\frac{55}{2}\)

\(=-\frac{275}{14}\)

d) \(\frac{4}{5}.\left(\frac{7}{2}+\frac{1}{4}\right)^2\)

\(=\frac{4}{5}.\left(\frac{14}{4}+\frac{1}{4}\right)^2\)

\(=\frac{4}{5}.\left(\frac{15}{4}\right)^2\)

\(=\frac{4}{5}.\frac{225}{16}\)

\(=\frac{45}{4}\)

Answer 2

a)\(\frac{21}{47}+\frac{9}{45}+\frac{26}{47}+\frac{4}{5}\)

=\(\frac{21}{47}+\frac{1}{5}+\frac{26}{47}+\frac{4}{5}\)

=\(\left(\frac{21}{47}+\frac{26}{47}\right)+\left(\frac{1}{5}+\frac{4}{5}\right)\)

=\(\frac{47}{47}+\frac{5}{5}=1+1=2\)

b)\(12.\left(-\frac{2}{3}\right)^2+\frac{4}{3}\)

=\(12.\frac{4}{9}+\frac{4}{3}\)

=\(\frac{12}{1}.\frac{4}{9}+\frac{4}{3}=\frac{48}{9}+\frac{4}{3}\)

=\(\frac{16}{3}+\frac{4}{3}=\frac{20}{3}\)

c)\(12,5.\left(-\frac{5}{7}\right)+1,5.\left(-\frac{5}{7}\right)\)

=\(\left(-\frac{5}{7}\right).\left(12,5+1,5\right)\)

=\(\left(-\frac{5}{7}\right).14=\left(-\frac{5}{7}\right).\frac{14}{1}=-10\)

d)\(\frac{4}{5}.\left(\frac{7}{2}+\frac{1}{4}\right)^2\)

=\(\frac{4}{5}.\left(\frac{14}{4}+\frac{1}{4}\right)^2\)

=\(\frac{4}{5}.\left(\frac{15}{4}\right)^2\)

=\(\frac{4}{5}.\frac{225}{16}\)

=\(\frac{900}{80}=\frac{45}{4}\)

Nhớ tick cho mình nha!