a) \(m_{NaOH}=6\cdot157.5\cdot\dfrac{1.06}{100}=10.017\left(g\right)\)
\(n_{NaOH}=\dfrac{10.017}{40}\simeq0.25\left(mol\right)\)
\(NaOH+CO_2\underrightarrow{t^0}NaHCO_3\)
\(n_{CO_2}=n_{NaOH}=0.25\left(mol\right)\)
\(n_{C_nH_{2n}}=\dfrac{2.8}{22.4}=0.125\left(mol\right)\)
\(C_nH_{2n}+\dfrac{3n}{2}O_2\underrightarrow{t^0}nCO_2+nH_2O\)
\(1.............................n\)
\(0.125..........................0.25\)
\(\Rightarrow n=\dfrac{0.25}{0.125}=2\)
\(CT:C_2H_4\)
\(CH_2=CH_2\)
b)
\(C_nH_{2n}+Br_2\rightarrow C_nH_{2n}Br_2\)
\(14n..............14n+160\)
\(10.08\cdot\cdot\cdot\cdot\cdot\cdot\cdot\cdot\cdot\cdot\cdot48.48\)
\(\Rightarrow48.48\cdot14n=10.08\left(14n+160\right)\)
\(\Rightarrow n=3\)
\(CT:C_3H_6\)
\(CH_2=CH-CH_3\)
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