Question

a) Chứng minh a // b
b) Tính góc C
 

Answer 1

\(a,\left\{{}\begin{matrix}a\perp AB\\b\perp AB\end{matrix}\right.\Rightarrow a//b\\ b,a//b\Rightarrow\widehat{C}+\widehat{B}=180^0\left(trong.cùng.phía\right)\\ \Rightarrow\widehat{C}=180^0-50^0=130^0\)

Answer 2

a) Ta có: a⊥AB,b⊥AB

=>a//b

b) Ta có: a//b

\(\Rightarrow\widehat{C}+\widehat{ADC}=180^0\)(trong cùng phía)

\(\Rightarrow\widehat{C}=180^0-50^0=130^0\)