\(a,3x-2=7.\)
\(3x=7+2.\)
\(3x=9.\)
\(x=\dfrac{9}{3}=3\in N.\)
Vậy.....
\(b,5x+4=\left(-3\right)+17.\)
\(5x+4=14.\)
\(5x=14-4.\)
\(5x=10.\)
\(x=\dfrac{10}{5}=2\in N.\)
Vậy.....
\(c,22-2x=4^{15}:4^{13}.\)
\(22-2x=16.\)
\(2x=22-16.\)
\(2x=6.\)
\(x=\dfrac{6}{2}=3\in N.\)
Vậy.....
a/ 3.x-2=7
3.x=7+2
3.x=9
x=9:3
x=3
Vậy x=3
b/5.x+4=(-3)+17
5.x+4=14
5.x=14-4
5.x=10
x=10:5
x=2
c/22-2.x=415:413
22-2.x=415-13
22-2.x=42
22-2.x=16
2.x=22-16
2.x=6
x=6:2
x=3