a) \(\left\{\left(\dfrac{3}{5}\right)^2-\left(\dfrac{2}{5}\right)^2\right\}x=\left(\dfrac{1}{5}\right)^3\)
\(\left(\dfrac{9}{25}-\dfrac{4}{25}\right)x=\dfrac{1}{125}\)
\(\dfrac{1}{5}x=\dfrac{1}{125}\)
\(x=\dfrac{1}{25}\)
b) Ý này đề bài rõ hơn đi ạ
c)\(\left(3x-2^2\right)=9\)
\(3x-4=9\)
\(3x=13\)
\(x=\dfrac{13}{3}\)
d)\(\left(x+\dfrac{1}{3}\right)-4=-1\)
\(x+\dfrac{1}{3}=3\)
\(x=\dfrac{8}{3}\)
a, \(\left[\left(\dfrac{3}{2}\right)^2-\left(\dfrac{2}{5}\right)^2\right]x=\left(\dfrac{1}{5}\right)^3\)
\(\Leftrightarrow\left(\dfrac{9}{4}-\dfrac{4}{10}\right)x=\dfrac{1}{125}\)
\(\Leftrightarrow\dfrac{1}{5}x=\dfrac{1}{125}\)
\(\Leftrightarrow x=\dfrac{1}{125}.5=\dfrac{1}{25}\)
b, Ghi lại đề
c, \(\left(3x-2^2\right)=9\)
\(\Leftrightarrow3x-4=9\)
\(\Leftrightarrow x=\dfrac{9+4}{3}=\dfrac{13}{3}\)
d, \(\left(x+\dfrac{1}{3}\right)-4=-1\)
\(\Leftrightarrow x=-1+4-\dfrac{1}{3}=3-\dfrac{1}{3}=\dfrac{8}{3}\)
