Question

a, (2x - 1) (x + 2) = 0

b, \(^{\left(x-3\right)^3}\) = 27

c, (2x\(^{^2}\) - \(\frac{1}{2}\)x)\(^{^x}\)=49

d, (2x\(^x\)-7x) . (x+5) - 5 = -5

Answer 1

a) (2x-1)(x+2)=0

<=> 2x-1=0

Hoặc x+2=0

<=>2x=1

Hoặc x=-2

<=>x=1/2

Hoặcx=-2

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Answer 2

b) (x-3)³=27

<=>(x-3)³=3³

<=>x-3=3

<=>x=6

Answer 3

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Answer 4

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Answer 5

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Answer 6

a, (2x - 1) (x + 2) = 0

⇔\(\left[{}\begin{matrix}2x-1=0\\x+2=0\end{matrix}\right.\)

⇔\(\left[{}\begin{matrix}2x=0+1\\x=0+2\end{matrix}\right.\)

⇔\(\left[{}\begin{matrix}2x=1\\x=2\end{matrix}\right.\)

⇔\(\left[{}\begin{matrix}x=2\\x=2\end{matrix}\right.\)

b,\(\left(x-3\right)^3=27\)

\(\left(x-3\right)^3=3^3\)

\(x-3=3\)

\(x=3+3\)

⇒\(x=6\)