Question

A=(-1/3x^5y^2).(-9xy^3) và B=(-1/2x^2y^3).(-x^2y^3)^3.Thu gọn a và b

Answer 1

\(A=\left(\dfrac{-1}{3}x^5y^2\right).\left(-9xy^3\right)\)

\(A=\left[\left(\dfrac{-1}{3}\right).\left(-9\right)\right].\left(x^5.x\right).\left(y^2.y^3\right)\)

\(A=3x^6y^5\)

 

\(B=\left(\dfrac{-1}{2}x^2y^3\right).\left(-x^2y^3\right)^3\)

\(B=\left(\dfrac{-1}{2}x^2y^3\right).\left(-x^2\right)^3.\left(y^3\right)^3\)

\(B=\left(\dfrac{-1}{2}x^2y^3\right).\left(-x^6\right).y^9\)

\(B=\left[\left(\dfrac{-1}{2}\right).\left(-1\right)\right].\left(x^2.x^6\right).\left(y^3.y^9\right)\)

\(B=\dfrac{1}{2}x^8y^{12}\)