ĐKXĐ: $x∈R$
$pt⇔9.(6-x-3)=(x-6)^2$
$⇔(x-6)^2+9(x-6)+27=0$
$⇔4(x-6)^2+36(x-6)+108=0$
$⇔4(x-6)^2+2.2(x-6).9+81=-27$
$⇔(2x-12+9)^2=-27$
$⇒pt$ vô nghiệm
A.(X+16/49) +(x+18/47)=(x+20/45)-1
B.(x-3/x-2)+(x-2/x-4)=-1
C.(4x-10).(x+6)=0
D.7x-1/2=5+(9-5x/6)
E.3.(7x-1)=30+9-5
F.(3x-9/x+1)-2=4x/x+1
Bài 5: Giải phương trình
a) x ( x+1) ( x – 1) ( x+2) =24
b) ( x – 4) ( x – 5) ( x – 6) ( x – 7) = 1680
c) 2x ( 8x – 1) 2 ( 4x – 1) = 9
d) ( 2x + 1)( x + 1) 2 ( 2x + 3) = 18
e) (x 2 – 6x +9 ) 2 – 15( x 2 – 6x +10) = 1
f) ( x 2 + 1) 2 + 3x ( x 2 + 1) + 2x 2 = 0
g) ( x 2 – 9) 2 = 12x + 1
Bài 6: Giải phương trình
a) ( x + 3) 4 + ( x+ 5 ) 4 = 16
b) ( x – 2) 4 + ( x – 3) 4 = 1
Bài 5: Giải phương trình
a) x ( x+1) ( x – 1) ( x+2) =24
b) ( x – 4) ( x – 5) ( x – 6) ( x – 7) = 1680
c) 2x ( 8x – 1) 2 ( 4x – 1) = 9
d) ( 2x + 1)( x + 1) 2 ( 2x + 3) = 18
e) (x 2 – 6x +9 ) 2 – 15( x 2 – 6x +10) = 1
f) ( x 2 + 1) 2 + 3x ( x 2 + 1) + 2x 2 = 0
g) ( x 2 – 9) 2 = 12x + 1
Bài 6: Giải phương trình
a) ( x + 3) 4 + ( x+ 5 ) 4 = 16
b) ( x – 2) 4 + ( x – 3) 4 = 1
Giải phương trình
a. x (x+1)(x-1)(x+2)=24
b.(x-4)(x-5)(x-6)(x-7)=1680
c. (x+2)(x+3)(x-5)(x-6)=180
d.2x(8x-1)2(4x-1)=9
e. (12x+7)2(3x+2)(2x+1)=3
g. (2x+1)(x+1)2(2x+3)=18
giải pt
1.(x^2-x+1)(X^2-x+2)=2
2.X(x+2)(x+3)(x+5)=280
3.(x+3)(x+4)(X+5)=x
4.\(\dfrac{1}{x\left(x+2\right)}+\dfrac{1}{\left(x+2\right)\left(x+4\right)}+\dfrac{1}{\left(x+4\right)\left(x+6\right)}=\dfrac{1}{9}\) 5. 12/x^2-12/x^2+2=1 6.(x^2-6x)^2+14(x-3)^2=81 7.(x^2+5x)^2-2(x^2+5x)-24=0
8. x^2+2x+3=(x^2+x+1)(X^4+x^2+4)
Giải các phương trình sau:
a) (x-1)(3x-7)=(x-1)(x+3)
b) (3x+1)(x-2)=(x-2)(x+1)
c) (x-3)^2 +2x-6=0
d)(2x-1)^2=9
e) x(x-1)=3(x-1)
f)x^2(x-3)=4(x-3)
g) x(x-5)=2(x-5)
1, \(\dfrac{\left(2x-3\right)\cdot\left(2x+3\right)}{8}=\dfrac{\left(x-4\right)^2}{6}+\dfrac{\left(x-2\right)^2}{3}\)
2, \(x+2-\dfrac{2x-\dfrac{2x-5}{6}}{15}=\dfrac{7x-\dfrac{x-3}{2}}{5}\)
3, \(1-\dfrac{x-\dfrac{1+x}{3}}{3}=\dfrac{x}{2}-\dfrac{2x-\dfrac{10-7}{3}}{2}\)
4, \(\dfrac{x+1}{99}+\dfrac{x+3}{97}+\dfrac{x+5}{95}=\dfrac{x+7}{93}+\dfrac{9+x}{91}+\dfrac{x+11}{89}\)
a) \(\frac{x-3}{5}=6-\frac{1-2x}{2}\)
b)\(\frac{3x-2}{6}-5=\frac{3-2\left(x+7\right)}{4}\)
c)\(2\left(x+\frac{3}{5}\right)=5-\left(\frac{13}{5}+x\right)\)
d)\(\frac{7x}{8}-5\left(x-9\right)=\frac{\left(20x+1.5\right)}{6}\)
