8X^2 - 6XY( 2X-Y) + 6X= 2Y^3 -6Y^2+ 18Y-14
Y^2 - 6Y + 5 + căn bậc ba (Y+1) (X^2 + 8) = 0
giải hpt
\(\left\{{}\begin{matrix}8x^3y^3+27=18y^3\\4x^2y+6x=y^2\end{matrix}\right.\)
Giải hệ
\(8x^3y^3+27=18y^3\)
\(4x^2y+6x=y^2\)
giải hệ phương trình: \(\left\{{}\begin{matrix}8x^3y^3+27=18y^3\\4x^2y+6x=y^2\end{matrix}\right.\)
\(\left\{{}\begin{matrix}2x^2+2y^2=1+2x+y\\2y^2+2x+y+1=6xy\end{matrix}\right.\)
\(\left\{{}\begin{matrix}y^3-x^3-x^2-y^2-xy^2+x^2y=6x-6y+6\\y\sqrt{x+3}+\left(y+6\right)\sqrt{x+10}=y^2+4x\end{matrix}\right.\)
giai he
\(\left\{{}\begin{matrix}\left(2x^2-3x+4\right)\left(2y^2-3y+4\right)=18\\x^2+y^2+xy-7x-6y+14=13\end{matrix}\right.\)
1)\(\begin{cases}y^3\left(3x^2-4x-23\right)=8-8y\\y^2\left(x^3+10x+27\right)=8x+6y\end{cases}\)
2\(\begin{cases}2\sqrt{x^2+5x-y+2}-2=\sqrt{y^2+8x}+x\\2y-\sqrt{x+1}=x+5\end{cases}\)
\(\begin{cases}2\sqrt{x^2+3x+2}-\sqrt{x+1}=2y\sqrt{y^2+1}+9-y-6y^2\\\sqrt{x^2+3x+2}+3\sqrt{x+1}=y\sqrt{y^2+1}-6+3y+4y^2\end{cases}\)
\(\begin{cases}x^2-y-1=2\sqrt{2x-1}\\y^3-8x^3+3y^2+4y-2x+2=0\end{cases}\)
\(\begin{cases}\left(x+\sqrt{x^2+4}\right)\left(y+\sqrt{y^2+1}\right)=2\\27x^6=x^3+4x+2\end{cases}\)
\(\begin{cases}x-\sqrt{3y-2}=\sqrt{9y^2-6y}-x\sqrt{x^2+2}\\x+y+\sqrt{y+3}=4\end{cases}\)