\(\frac{8}{6}x+2=x-3\)
\(\frac{8}{6}x-x=-3-2\)
\(\frac{1}{3}x=-5\)
\(x=-\frac{1}{15}\)
Vậy x= \(-\frac{1}{15}\)
\(\frac{8}{6}\)x+2=x-3
\(\Leftrightarrow\)\(\frac{8}{6}\)x-x=-2-3
\(\Leftrightarrow\)\(\frac{1}{3}\)x=-5
\(\Leftrightarrow\)x=-5:\(\frac{1}{3}\)
\(\Leftrightarrow\)x=-15
Vậy x=-15
\(\frac{8}{6}x+2=x-3\\ \frac{8}{6}x-x=-2-3\\ \frac{8}{6}x-x=-5\\ \frac{1}{3}x=-5\\ x=-5:\frac{1}{3}\\ x=-15\)
chuyển vế đổi dấu
\(\frac{8}{6x+2}\)=x-3
\(\Rightarrow\)(6x+2)(x-3)=8
\(\Rightarrow\)6x\(^2\)-18x+2x-6=8
\(\Rightarrow\)6x\(^2\)-18x+2x-6-8=0
\(\Rightarrow\)6x\(^2\)-16x-14=0