Ta có: \(6x+x=5^{11}:5^9+3^1\\ < =>7x=5^2+3^1\\ < =>7x=25+3=28\\ =>x=\dfrac{28}{7}=4\)
Có:
\(6x+x=\dfrac{5^{11}}{5^9}+3^1\)
\(\Rightarrow7x=5^2+3=25+3=28\)
\(\Rightarrow x=\dfrac{28}{7}=4\)
Vậy \(x=4\).
Học tốt!
\(6x+x=5^{11}:5^9+3^1\)
\(\Leftrightarrow7x=5^{11-9}+3\)
\(\Leftrightarrow7x=5^2+3=25+3=28\)
\(\Leftrightarrow x=28:7=4\)
Vậy \(x=4\)
Chúc bạn học tốt!!!
6x + x = 511:59 + 31
=> 7x = 52 + 31
=> 7x = 28
=> x = 28 : 7
=> x = 4
