Question

-6/6 < -4/... < -6/8

điền vô :)

 

Answer 1

\(\dfrac{-6}{6}< \dfrac{-4}{a}< \dfrac{-6}{8}\\ \Rightarrow\dfrac{-12}{12}< \dfrac{-12}{3a}< \dfrac{-12}{16}\\ \Rightarrow3a\in\left\{13;14;15\right\}\\ \Rightarrow a\in\left\{\dfrac{13}{3};\dfrac{14}{3};5\right\}\)

Answer 2

Gọi x là số cần tìm:      (x \(\ne0\))

\(\dfrac{-6}{6}< \dfrac{-4}{x}< \dfrac{-6}{8}\)

<=> \(\dfrac{-24}{24}< \dfrac{-24}{6x}< \dfrac{-24}{32}\)

<=> 24 < 6x < 32

<=> \(6x\in\left\{25;26;27;28;29;30;31\right\}\)

<=> \(x\in\left\{4,1\left(6\right);4\left(3\right);4,5;4,\left(6\right);4,8\left(3\right);5;5,1\left(6\right)\right\}\)