Tìm x:
6x(3x+5)-2x(9x-2)=17
2x(3x-1)-3x(2x+11)-70=0
Tìm x :
a) \(\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
b) \(\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
c) \(\dfrac{x+2014}{2}+\dfrac{2x+4028}{7}=\dfrac{x+2009}{5}+\dfrac{x+2020}{6}\)
d)\(\dfrac{3}{\left(x+2\right)\left(x+5\right)}+\dfrac{5}{\left(x+5\right)\left(x+10\right)}+\dfrac{7}{\left(x+10\right)\left(x+18\right)}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
Help me , bn nào giải đc bài nò thì giải nha !!! =))
(6-3x)(-2x+5);
X^2+x
3x-3
6-2x
3/2- |3x| = 17/6
tìm x nguyên thỏa mãn: \(\frac{2x+2}{3x-6}=\frac{2x-6}{3x-15}\)
Cho đa thức : P ( x ) = 3\(x^2-1+2x^6-3x^5-x^2+5x+3x^5-2x^6\)
Tìm nghiệm của H ( x ) biết P(x) - H(x ) = -1
Tìm x, biết :
\(\left|3x-4\right|-\left|x+2\right|=6\)
tim nghiem cua da thuc:
M(x)=(6-3x)(-2x+5)
N(x)=x^2+x
A(x)=3x-3
bài 1: tính
a) -6x+3(7+2x)
b)15y-5(6x+3y)
c) x(2x+1)-x2(x+2)+(x3-x+3)
d)4(x-6)-x2(2+3x)+x(5x-4)3x2(x-1)
bài 2: tìm x
a)3x+2(5-x)=0
b)3x2-3x(-2+x)=36
c)5x(12x+7)-3x(20x-5)=-100