Question

4x-1/9=0

Answer 1

4x- \(\dfrac{1}{9}\) = 0

4x = 0 + \(\dfrac{1}{9}\)

4x = \(\dfrac{1}{9}\)

x = \(\dfrac{1}{9}\) : 4

x = \(\dfrac{1}{36}\)

Answer 2

\(\dfrac{4x-1}{9}=0\)

\(\Leftrightarrow4x-1=0\)

\(\Leftrightarrow4x=1\)

\(\Leftrightarrow x=\dfrac{1}{4}\)