Ta có: \(4.\left(5-x\right)-3.\left(1-x\right)=-3^2\)
\(\Leftrightarrow20-4x-3+3x=9\)
\(\Leftrightarrow-4x+3x=9-20+3\)
\(\Leftrightarrow-x=-8\)
\(\Leftrightarrow x=8\)
Vậy: \(x=8\)
Ta có: \(3.\left|2x-3\right|=7-\left(-14\right)\)
\(\Leftrightarrow3.\left|2x-3\right|=7+14=21\)
\(\Leftrightarrow\left|2x-3\right|=\dfrac{21}{3}=7\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=7\\2x-3=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=10\\2x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-2\end{matrix}\right.\)
Vậy: \(x=-2;5\)
Ta có: \(2^{2x-1}-3^2=23\)
\(\Leftrightarrow2^{2x-1}-9=23\)
\(\Leftrightarrow2^{2x-1}=32\)
\(\Leftrightarrow2^{2x-1}=2^5\)
\(\Leftrightarrow2x-1=5\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
Vậy: \(x=3\)
_Chúc bạn học tốt_
