Question

4\(^2\)x 120 -4\(^3\):\(\frac{1}{7}\)+ 4\(^2\)x34

Answer 1

\(4^2.120-4^3:17+4^2.34\)

\(=4^2.120-4^3.\frac{1}{7}+4^2.34\)

\(=4^2.\left(120-\frac{4}{17}+34\right)\)

\(=4^2.\frac{2614}{17}\)

\(=\frac{41824}{17}\)

 

Answer 2

\(4^2\times120-4^3\div\frac{1}{7}+4^2\times34\)

\(=4^2\left(120+34\right)-4^2\times7\times4\)

\(=4^2\times154-4^2\times7\times4\)

\(=4^2\left(154+7\right)\times4\)

\(=4^2\times161\times4\)

\(=4^3\times161\)

\(=64\times161\)

\(=10304\)