\(3\cdot\left(x-\dfrac{1}{2}\right)-5\cdot\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{5}\\ \left(3x-\dfrac{3}{2}\right)-\left(5x+3\right)=-x+\dfrac{1}{5}\\ 3x-\dfrac{3}{2}-5x-3=-x+\dfrac{1}{5}\\ 3x-5x+x=\dfrac{1}{5}+\dfrac{3}{2}+3\\ -x=\dfrac{47}{10}\\ x=\dfrac{-47}{10}\)