\(3^{x+3}+3^{x+1}=270\)
\(\Rightarrow3^x.3^3+3^x.3=270\)
\(\Rightarrow3^x.\left(3^3+3\right)=270\)
\(\Rightarrow3^x.30=270\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
\(3^{x+3}+3^{x+1}=270\)
\(\Rightarrow3^x.3^3+3^x.3=270\)
\(\Rightarrow3^x.\left(3^3+3\right)=270\)
\(\Rightarrow3^x.30=270\)
\(\Rightarrow3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
Tìm x:
1) 280-(x-140):35=270 4) x17=x
2) 720:[41-(2x-5)]=23.5 5) 5x:52=125
3) (3x-4).(x-1)3=0 6)(x+2)5=210
\(\left(3x+1\right)^2=\left(3x+1\right)^3\)
Tìm x
\(\frac{3^{3x}+3^{3x+2}}{3^3}=\frac{4^{2x+1}+4^{2x}}{2^3}\)
1.Tìm x
(3x-1).(1/2x5)=0
1/4+1/3:(2x-1)=5
(2x+2/5)mũ 2-9/25=0
(3x-1/2)mũ 3+1/9=0
Tìm x,y biết:
a) \(-\dfrac{1}{2}\left(3-2x\right)-7=5-\dfrac{1}{3}\left(x-\dfrac{4}{5}\right)\)
b)\(\left(5-\dfrac{3x}{2}\right):-1\dfrac{3}{8}=-7\dfrac{1}{3}\)
c)\(\left(2+3x\right)^2+\left|3x+2y\right|=0\)
(1-3x)+(x-3)=(5x-1)-(5x+3)
Tìm x, biết: 3x/2*5 + 3x/5*8 + 3x/8*11 + 3x/11*14 = 1/21
(3x + 1)^3 = 64
2x-3=3x+1
Tìm số nguyên x
1/ \(17x+3\left(-16x-37\right)=2x+43-4x\)
2/ \(-2x-3\left(x-17\right)=34-2\left(-x+25\right)\)
3/ \(\left\{-3x+2\left[45-x-3\left(3x+7\right)-2x\right]+4x\right\}=55-103-57:\left[-2\left(2x-1\right)^2-\left(-9\right)^0\right]=-106\)
4/ \(-2x+3\left\{12-2\left[3x-\left(20+2x\right)-4x\right]+1\right\}=45\)
5/ \(3x-32>-5+1\)
6/ \(15+4x< 2x-145\)
7/ \(-3\left(2x+5\right)-16< -4\left(3-2x\right)\)
8/ \(-2x+15< 3x-7< 19-x\)