Question

\(3x^2+4x-4=0\)

Answer 1

Binh Le đề bài là j vậy

Answer 2

\(3x^2+4x-4=0\)

\(3x^2+6x-2x-4=0\)

\(3x\left(x+2\right)-2\left(x+2\right)=0\)

\(\left(x+2\right)\left(3x-2\right)=0\)

\(\left[{}\begin{matrix}x=-2\\x=\dfrac{2}{3}\end{matrix}\right.\)

Answer 3

\(3x^2+4x-4=0\)

\(\Leftrightarrow\)\(3x^2-6x+2x-4=0\)

\(\Leftrightarrow3x\left(x-2\right)+2\left(x-2\right)=0\)

\(\Leftrightarrow\left(3x+2\right)\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}3x+2=0\\x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{-2}{3}\\x=2\end{matrix}\right.\)