Ta có: \(\left|3x-5\right|=\frac{3}{5}\)
\(\Rightarrow\left[\begin{matrix}3x-5=\frac{3}{5}\\3x-5=-\frac{3}{5}\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=\frac{28}{15}\\x=\frac{22}{15}\end{matrix}\right.\)
Vậy: \(x=\frac{28}{15}\) hoặc \(\frac{22}{15}\)
Ta có:
\(\left|3x-5\right|=\frac{3}{5}\)
=> \(\left[\begin{matrix}3x-5=\frac{3}{5}\\3x-5=\frac{-3}{5}\end{matrix}\right.\)
=> \(\left[\begin{matrix}3x=\frac{3}{5}+5\\3x=\frac{-3}{5}+5\end{matrix}\right.\)
=> \(\left[\begin{matrix}3x=\frac{28}{5}\\3x=\frac{22}{5}\end{matrix}\right.\)
=> \(\left[\begin{matrix}x=\frac{28}{5}:3\\x=\frac{22}{5}:3\end{matrix}\right.\)
=> \(\left[\begin{matrix}x=\frac{28}{15}\\x=\frac{22}{15}\end{matrix}\right.\)
Vậy \(\left[\begin{matrix}x=\frac{28}{15}\\x=\frac{22}{15}\end{matrix}\right.\).
\(\left|3x-5\right|=\frac{3}{5}\)
\(\Rightarrow\left[\begin{matrix}3x-5=\frac{3}{5}\\3x-5=\frac{-3}{5}\end{matrix}\right.\)
\(\Rightarrow\left[\begin{matrix}3x=\frac{3}{5}+5\\3x=\frac{-3}{5}+5\end{matrix}\right.\)
\(\Rightarrow\left[\begin{matrix}3x=\frac{28}{5}\\3x=\frac{22}{5}\end{matrix}\right.\)
\(\Rightarrow\left[\begin{matrix}x=\frac{28}{15}\\x=\frac{22}{15}\end{matrix}\right.\)