\(-3x-\left(-17\right)=14\)
\(-3x+17\) \(=14\)
\(-3x\) \(=14-17\)
\(-3x\) \(=-3\)
\(x\) \(=-3\div\left(-3\right)\)
\(x\) \(=1\)
Vậy \(x=1\)
\(-3x-\left(-17\right)=14\)
\(\Leftrightarrow-3x+17=14\)
\(\Leftrightarrow-3x=14-17\)
\(\Leftrightarrow-3x=-3\)
\(\Leftrightarrow x=\frac{-3}{-3}\)
\(\Leftrightarrow x=1\)
Vậy : \(x=1\)
−3x−(−17)=14
⇔−3x+17=14
⇔−3x=14−17
⇔−3x=−3
⇔x=\(\frac{-3}{-3}\)
⇔x=1
Vậy : x=1
\(-\)3\(x\) - ( 17 ) = 14
⇔ \(-\) 3\(x\) + 17 = 14
⇔ \(- \) 3\(x\) = 14 \(-\) 17
⇔ \(-\) 3\(x\) \(-\) 3
⇔ \(x\) = \(\frac{-3}{-3}\)
⇔ \(x\) = 1
Vậy : \(x\) = 1
hok tốt
-3x+17=14
-3x=14-17
-3x= -3
x= -3: (-3)
x=1
-3x-(-17)=14
-3x+17=14
-3x =14-17
-3x =-3
x =-3:(-3)
x =1
-3x -(-17)=14
-3x + 17 =14
-3x=14-17=[14+(-17)]=[-17+14]=-3
x=-3:(-3)=1
Vậy x=1