3 + \(\left|x-1\right|\) = 2(x-1)
\(\Leftrightarrow\) \(\left|x-1\right|\)= 2x -5
+ Nếu x + 1 \(\ge\) 0 \(\Rightarrow\) x \(\ge\) -1 thì
\(x - 1 = 2x - 5 \)
\(\Leftrightarrow\)\( x - 2x = -5 + 1 \)
\(\Leftrightarrow\) \(- x = - 4 \)
\(\Leftrightarrow\)\( x = 4 \)(thõa mãn)
+ Nếu x - 1 < 0 \(\Rightarrow\) x < 1 thì:
\(- (x - 1) = 2x -5\)
\(\Leftrightarrow\)\(-x-2x=-5-1\)
\(\Leftrightarrow\)\(-3x = -6\)
\(\Leftrightarrow\) \(x = 2 \) (loại)
Vậy \( x = 4 \)