\(PTHH:AgNO_3+NaCl\rightarrow AgCl+NaNO_3\)
\(\left\{{}\begin{matrix}n_{AgNO3}=0,1\left(mol\right)\\n_{NaCl}=0,2\left(mol\right)\end{matrix}\right.\)
=> Tính theo agno3
\(\Rightarrow n_{AgCl}=n_{AgNO3}=0,1\left(mol\right)\)
\(\Rightarrow m_{AgCl}=0,1.143,5=14,35\left(g\right)\)