\(\dfrac{3}{2x+3}=\dfrac{5}{3x-2}\)
\(\Rightarrow3\left(3x-2\right)=5\left(2x+3\right)\)
\(\Rightarrow9x-6=10x+15\)
\(\Rightarrow0=x+21\)
\(\Rightarrow x=-21\)
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\(\dfrac{3}{2}x+3=\dfrac{5}{3}x-2\)
\(\Leftrightarrow\dfrac{3}{2}x+3-\left(\dfrac{5}{3}x-2\right)=0\)
\(\Leftrightarrow\dfrac{3}{2}x+3-\dfrac{5}{3}x+2=0\)
\(\Leftrightarrow5-\dfrac{1}{6}x=0\)
\(\Leftrightarrow\dfrac{1}{6}x=5\)
\(\Leftrightarrow x=30\)
Vậy x=30
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