\(\dfrac{3}{10}+\dfrac{2}{3}:\dfrac{5}{6}-\dfrac{3}{5}x\dfrac{5}{3}=\dfrac{3}{10}+\dfrac{4}{5}-1=\dfrac{3}{10}+\dfrac{8}{10}-\dfrac{10}{10}=\dfrac{1}{10}\)
\(30\%+\dfrac{2}{3}:\dfrac{5}{6}-0,6\cdot1\dfrac{2}{3}=\dfrac{3}{10}+\dfrac{2}{3}:\dfrac{5}{6}-\dfrac{3}{5}\cdot\dfrac{5}{3}=\dfrac{3}{10}+\dfrac{4}{5}-1=\dfrac{11}{10}-1=\dfrac{1}{10}\)