Question

(3 . x - 48) . 6 = 3³ . 3³ + 2³ + 3² - 12²

Answer 1

\(\left(3x-4x\right)\cdot6=3^3\cdot3^3+2^3+3^2-12^2\)

\(\Leftrightarrow18x-288=3^6+2^3+3^2-12^2\)

\(\Leftrightarrow18x-288=729+8+\left(3-12\right)\cdot\left(3+12\right)\)

\(\Leftrightarrow18x-288=729+8+\left(-9\right)\cdot15\)

\(\Leftrightarrow18x-288=729+8-135\)

\(\Leftrightarrow18x-288=602\)

\(\Leftrightarrow18x=602+288\)

\(\Leftrightarrow18x=890\)

\(\Rightarrow x=\dfrac{445}{9}\)

Vậy \(x=\dfrac{445}{9}\)

Answer 2

(3x-48).6=3³.3³+2³+3²-12²

(3x-48).6=3⁶+8+9-144

(3x-48).6=729+-127

(3x-48).6= 602

3x-48=\(\dfrac{602}{6}\)

3x=\(\dfrac{602}{6}\)+48

3x=\(\dfrac{445}{3}\Leftrightarrow x=\dfrac{445}{9}\)