\(2x^4+12x^3+14x^2-2x-6\\ =2x^4+2x^3+10x^3+10x^2+4x^2+4x-6x-6\\ =2x^3\left(x+1\right)+10x^2\left(x+1\right)+4x\left(x+1\right)-6\left(x+1\right)\\ =\left(2x^3+10x^2+4x-6\right)\left(x+1\right)\)
2x4 + 12x3 + 14x2 - 2x - 6
= 2x4 + 2x3 + 10x3 + 10x2 + 4x2 + 4x - 6x - 6
= ( x + 1 ) ( 2x3 + 10x2 + 4x - 6 )
Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:
\(a,\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
\(b,\frac{x+1}{3}+\frac{3\left(2x+1\right)}{4}=\frac{2x+3\left(x+1\right)}{6}+\frac{7+12x}{12}\)
Bài 1
a) 2x^3 + 5x^2 + 5x + 3
b) 4x^3 + x^2 + x - 3
c) 5x^3 - 12x^2 + 14x - 4
d) 6x^3 - 7x^2 + 5x - 2
e) 3x^3 + 19x^2 + 4x - 12
(x-2)2/3-(2x-3)(x+3)/8+(x-4)/6=0
(2x+1)2/5-(x-1)2/3=(7x2-14x-5)/15
giải phương trình sau :
a) 5-(x-6) = 4(3-2x) b) 2x(x+2)2-8x2 = 2(x-2)(x2+4)
c) 7-(2x+4) = -(x+4) d) (x+1)(2x-3) = (2x-1)(x+5
f) \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\)
e) \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x-1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
Cho biểu thức: \(M=\left(\dfrac{1+2x}{4+2x}-\dfrac{x}{3x-6}+\dfrac{2x^2}{12-3x^2}\right).\dfrac{24+12x}{6+13x}\)
Cho biểu thức: \(M=\left(\dfrac{1+2x}{4+2x}-\dfrac{x}{3x-6}+\dfrac{2x^2}{12-3x^2}\right).\dfrac{24+12x}{6+13x}\). Rút gọn M
Phân tích đa thức thành nhân tử:
a, 2x4 + 3x3 - 9x2 - 3x +2
b, x4- 3x3- 6x2 + 3x +1
c, x4 - 6x3+12x2 -14x+3
d, x4 - 8x+63
e, x4 - 8x4 -x +12
1. x2-8x+16
2.(x+5)(x-5)
3.x3-6x2+12x-8
4.(x+2)(x2-2x+4)
5.x2+2x+1
6.x2-1
Thực hiện các phép chia:
1) 3xy2 : 5x
2) 15x4yz3 : 4xyz
3) (4x2y2 - 12xy3 - 7x) : 3x
4) (14x4y2 - 12xy3 - x) : 4x
5) (6x2 + 13x - 5) : (2x + 5)
6) (2x4 + x3 - 5x2 - 3x - 3) : (x2 -3)
