\(\dfrac{2}{x+3}-\dfrac{x}{3-x}-\dfrac{3x^2}{x^2-9}=\dfrac{2x-6+x^2+3x-3x^2}{\left(x-3\right)\left(x+3\right)}=\dfrac{-2x^2+5x-6}{\left(x-3\right)\left(x+3\right)}\)
\(\dfrac{2}{x+3}-\dfrac{x}{3-x}-\dfrac{3x^2}{x^2-9}=\dfrac{2x-6+x^2+3x-3x^2}{\left(x-3\right)\left(x+3\right)}=\dfrac{-2x^2+5x-6}{\left(x-3\right)\left(x+3\right)}\)
Chủ đề 1: Thực hiện phép tính
1) (2x+3).(2x-3)-4x.(x+5)
2) 6/x2 - 9 + 5/x-3 + 1/x+3
3)5x.(x-3)+(x-2)2
4) 4x/x+2 - 3x/x-2 + 12x/ x2 - 4
5) x(x+2) - ( x-3)(x+3)
6) 1/3x-2 + -4/3+2 + 6-3x/9x2 - 4
7)2x.(3x-1)+(x+2)2
8) 6/x+3 - 6/x-3 + 9x+9/x2 - 9
9) (2x - 5)2 - x(4x-13)
10) x-1/x + 4/x+8 + 8/x2 + 8x
11) (2x+1)2 + (x-5)(x+5)-x(5x+7)
12) 6/x2-9 + 5/x-3 + 1/x+3
13) 6x(5x-2)+(2x+3)2
14) x/x-2 + -2/x-3 + x(1-x)/x2-9
15) (x-2)2-x(x+5)
16) 2/x+3 + 3/x-3 + -6/x2-9
17) 3x(x-3) + (3x-1)2
Đẳng thức nào đúng:
A.(x-3)^2=x^2+6x+9 B.(x-3)^2=9-x^2
C.(x-3)^2=9-6x+x^2 D.(x-3)^2=x^2-3x+9
Bài 1: Tính:
a) x^2-9/2x+6 : 3-x/2
b) 2x/x-y - 2y/x-y
c) x+15/x^2-9 + 2/x+3
d)x+y/2x+2y - x-y/2x+2y - y^2+x^2/y^2-x^2
Bài 2: Rút gọn:
a) x^3-x/3x+3
b) x^2+3xy/x^2-9y^2
Bài 3: Thực hiện phép tính:
a) x/x-3 + 9-6x/x^2-3x
b) 6x-3/x : 4x^2-1/3x^2
Rút gọn M và A sau đây :
M= \(\left(\dfrac{x}{x+3}+\dfrac{3-x}{x+3}.\dfrac{x^2+3x+9}{x^2-9}\right)\)
A= \(\left(\dfrac{3x}{1-3x}-\dfrac{2x}{3x+1}\right):\dfrac{6x^2+10x}{1-6x+9x^2}\)
Thực hiện phép tính:
a) \(\dfrac{x^2}{x-1}+\dfrac{1-2x}{x-1}\)
b) \(\dfrac{x}{x-3}+\dfrac{-9}{x^2-3x}\)
c) \(\dfrac{3}{x-3}-\dfrac{6x}{9-x^2}+\dfrac{x}{x+3}\)
d) \(\dfrac{5x+10}{4x-8}.\dfrac{x-2}{x+2}\)
e) \(\dfrac{4x+6y}{x-1}:\dfrac{4x^2+12xy+9y^2}{1-x^2}\)
giải phương trình
a.\(\left(2x-3\right)^2=\left(2x-3\right)\left(x+1\right)\)
b.\(x\left(2x-9\right)=3x\left(x-5\right)\)
c.\(3x-15=2x\left(x-5\right)\)
d.\(\dfrac{5-x}{2}=\dfrac{3x-4}{6}\)
e.\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=2x+\dfrac{5}{3}\)
1) x(x-3)-2x(x-3)=0
2) x(3x-1)-5(1-3x)=0
3) 5(x+3)-2x(3x+3)=0
4) 4x(x+3)-x-3=0
5) x3+15x2+75x+125=0
6) 4x2-12x+9=0
7) x2-16x+60=0
8) x3+48x=12x2+64
Rút gọn:
(\(\dfrac{9}{x^{ }^3-9x}+\dfrac{1}{x+3}\)) : ( \(\dfrac{x-3}{x^2+3x}-\dfrac{x}{x^2-9}\))
Rút gọn:
\(\dfrac{9}{x^3-9x}+\dfrac{1}{x+3}\) ) : (\(\dfrac{x-3}{x^2+3x}-\dfrac{x}{x^2-9}\))