\(2^x.2^{x+3}=64^2:2^5\)
\(2^x.2^x.2^3=2^{12}:2^5\)
\(2^x.\left(1+8\right)=2^7\)
\(2^x.9=2^7\)
\(\Rightarrow x=\varnothing\)
\(2^{2x+3}=64^2:2^5\)
\(\Leftrightarrow2^{2x+3}=2^7\)
hay x=2
\(2^x.2^{x+3}=64^2:2^5\)
\(\Leftrightarrow\)\(2^x.2^{x+3}=128\)
\(\Leftrightarrow\)\(2^x.2^{x+3}=2^7\)
\(\Leftrightarrow\)\(x+x+3=7\)
\(\Leftrightarrow\)\(x=2\)