\(2x^2-7x+3=2x^2-6x-x+3=2x\left(x-3\right)-\left(x-3\right)=\left(2x-1\right)\left(x-3\right)\)
\(3x^2+7x-76=3x^2-12x+19x-76=3x\left(x-4\right)+19\left(x-4\right)=\left(3x+19\right)\left(x-4\right)\)
\(\dfrac{1}{2}x^2-\dfrac{19}{6}x+1=\dfrac{1}{2}x^2-3x-\dfrac{1}{6}x+1=x\left(\dfrac{x}{2}-3\right)-\dfrac{1}{3}\left(\dfrac{x}{2}-3\right)=\left(x-\dfrac{1}{3}\right)\left(\dfrac{x}{2}-3\right)\)
\(2x^2-5x-3\): sai đề
\(15x^2-x-6=15x^2-10x+9x-6=5x\left(3x-2\right)+3\left(3x-2\right)=\left(5x+3\right)\left(3x-2\right)\)
\(3x^2+5x-2=3x^2+6x-x-2=3x\left(x+2\right)-\left(x+2\right)=\left(3x-1\right)\left(x+2\right)\)
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