\(\left(2x-3\right)-5=7\)
\(\left(2x-3\right)=7+5\)
\(\left(2x-3\right)=12\)
\(2x=12-3\)
\(2x=9\)
\(x=9:2\)
\(x=4,5\)
\(|2x-3|-5=7\)
\(\Rightarrow|2x-3|=7+5=12\)
Trường hợp 1: \(2x-3=12\Rightarrow2x=15\Rightarrow x=\dfrac{15}{2}\)
Trường hợp 2: \(2x-3=-12\Rightarrow2x=-9\Rightarrow x=-\dfrac{9}{2}\)
Vậy \(x=\dfrac{15}{2}\) hoặc \(x=-\dfrac{9}{2}\)
\(|\)2x-3\(|\)-5=7
\(|\)2x-3\(|\)=7+5
\(|\)2x-3\(|\)=12
\(\Rightarrow\left[{}\begin{matrix}2x-3=12\\2x-3=-12\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}2x=15\\2x=-9\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=\dfrac{-9}{2}\end{matrix}\right.\)
Vậy x=\(\dfrac{15}{2}\) hoặc x=\(\dfrac{-9}{2}\) thì \(|2x-3|-5=7\)
