\(2x+\dfrac{1}{3}x=-\dfrac{14}{5}\)
\(\dfrac{7}{3}x=-\dfrac{14}{5}\Rightarrow x=-\dfrac{6}{5}\)
\(\Leftrightarrow x.\left(2+\dfrac{1}{3}\right)=-\dfrac{14}{5}\\ \Leftrightarrow x.\dfrac{7}{3}=-\dfrac{14}{5}\\ \Leftrightarrow x=-\dfrac{14}{5}.\dfrac{3}{7}=-\dfrac{6}{5}\)
2x + \(\dfrac{1}{3}\)x = \(\dfrac{-14}{5}\)
x(2 + \(\dfrac{1}{3}\)) = \(\dfrac{-14}{5}\)
\(\dfrac{7}{3}\)x = \(\dfrac{-14}{5}\)
x = \(\dfrac{-6}{5}\)