Ta có :
\(\left|2x-1\right|=\left|2x+3\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=-2x+3\\2x-1=2x+3\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}4x=-2\\2x-1-2x-3=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-1}{2}\left(tm\right)\\-4=0\left(loại\right)\end{matrix}\right.\)
Vậy ...
| 2x - 1 | = | 2x + 3 |
=> \(\left[{}\begin{matrix}2x-1=2x+3\\2x-1=-2x+3\end{matrix}\right.\)
1) 2x - 1 - 2x - 3 = 0
( 2x - 2x ) - ( 1 + 3 ) = 0
-4 = 0 ( ktm )
2) 2x - 1 = -2x + 3
2x - 1 + 2x - 3 = 0
( 2x + 2x ) - ( 1 + 3 ) = 0
4x - 4 = 0
4x = 4
x = 1 ( tm )
Vậy x = 1
