a) nNa2O = \(\dfrac{31}{62}=0,5\left(mol\right)\)
mdd NaOH = 1,25 . 200 = 250 (g)
Pt: Na2O + H2O --> 2NaOH
....0,5 mol-----------> 1 mol
mNaOH = 1 . 40 = 40 (g)
C% dd NaOH = \(\dfrac{40}{250}.100\%=16\%\)
CM NaOH = \(\dfrac{1}{0,2}=5M\)
P/s: câu b đề thiếu